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10h^2+30h+20=0
a = 10; b = 30; c = +20;
Δ = b2-4ac
Δ = 302-4·10·20
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-10}{2*10}=\frac{-40}{20} =-2 $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+10}{2*10}=\frac{-20}{20} =-1 $
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